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Question

Physics Question on Dual nature of matter

One milligram of matter converted into energy, will give

A

9J9\, J

B

9×103J9\times 10^{3}J

C

9×105J9\times 10^{5}J

D

9×1010J9\times 10^{10}J

Answer

9×1010J9\times 10^{10}J

Explanation

Solution

From Einstein's mass-energy equivalence relation, the amount of matter converted into energy is given by
ΔE=Δmc2\Delta E=\Delta m c^{2}
Given, Δm=1mg=106kg\Delta m=1\, mg =10^{-6} kg,
c=3×108m/sc=3 \times 10^{8} m / s
ΔE=(106)(3×108)2\therefore \Delta E=\left(10^{-6}\right)\left(3 \times 10^{8}\right)^{2}
ΔE=9×1010J\Rightarrow \Delta E=9 \times 10^{10} J