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Question: One litre of a gas is collected at STP. What would be the volume of the same gas at 2 atmospheric pr...

One litre of a gas is collected at STP. What would be the volume of the same gas at 2 atmospheric pressure and 27 !!!! C\text{27 }\\!\\!{}^\circ\\!\\!\text{ C}:
(A) 300!!×!! 273 litre\dfrac{\text{300}}{\text{2 }\\!\\!\times\\!\\!\text{ 273}}\text{ litre}
(B) !!×!! 300273 litre\dfrac{\text{2 }\\!\\!\times\\!\\!\text{ 300}}{\text{273}}\text{ litre}
(C) 273!!×!! 300 litre\dfrac{\text{273}}{\text{2 }\\!\\!\times\\!\\!\text{ 300}}\text{ litre}
(D) !!×!! 273300 litre\dfrac{\text{2 }\\!\\!\times\\!\\!\text{ 273}}{\text{300}}\text{ litre}

Explanation

Solution

Recollect the concept of STP. Find out the difference between STP and NTP. The question says 1 litre of gas is collected at STP and we need to find the volume of the same gas at different conditions of temperature and pressure. By using combined gas law, we can relate pressure, volume and temperature at two different conditions. Use this law and just substitute the values to get the answer.

Complete step by step solution:
STP stands for standard temperature pressure which is a standard set of reaction conditions of experimental data for establishing a comparison between a wide range of data sets. At STP, the temperature is 273K and pressure is 1atm.
NTP stands for normal temperature pressure wherein temperature is 293K and pressure is 1atm.
In the given question, we have to write the initial and the final conditions at first. So, the initial conditions go as follows:
The Initial Pressure or P1{{\text{P}}_{\text{1}}}is 1 atm,
The Initial Volume or V1{{\text{V}}_{\text{1}}}is 1 Litre,
The Initial Temperature or T1{{\text{T}}_{\text{1}}} is 273 K.
Now the final conditions are given as:
The Final Pressure or P2{{\text{P}}_{\text{2}}} is 2 atm,
The Final Volume of V2{{\text{V}}_{\text{2}}} is to be found out by us.
The Final Temperature or T2{{\text{T}}_{\text{2}}} is (273 + 27) = 2 = 300 K
By Combined Gas Law we have,
P1V1T1 = P2V2T2\dfrac{{{\text{P}}_{\text{1}}}{{\text{V}}_{\text{1}}}}{{{\text{T}}_{\text{1}}}}\text{ = }\dfrac{{{\text{P}}_{\text{2}}}{{\text{V}}_{\text{2}}}}{{{\text{T}}_{\text{2}}}}
Now substituting the values in the above equation, we get:
!!×!! 1 273 = !!×!! V2300 V2 = 300!!×!! 273 litre \begin{aligned} & \dfrac{\text{1 }\\!\\!\times\\!\\!\text{ 1 }}{\text{273}}\text{ = }\dfrac{\text{2 }\\!\\!\times\\!\\!\text{ }{{\text{V}}_{\text{2}}}}{\text{300}} \\\ & {{\text{V}}_{\text{2}}}\text{ = }\dfrac{\text{300}}{\text{2 }\\!\\!\times\\!\\!\text{ 273}}\text{ litre} \\\ \end{aligned}

Hence, we can say that the correct answer is Option A.

Note: STP is standards set by the International Union of Pure and Applied Chemistry (IUPAC) and the National Institute of Standards and Technology (NIST). By using combined gas law which gives the relationship between pressure, volume and temperature, these kinds of problems can be easily solved.