Question
Question: One kilogram of seawater sample contains \[6mg\] dissolved \[{O_2}\]. The concentration \[{O_2}\] in...
One kilogram of seawater sample contains 6mg dissolved O2. The concentration O2 in the sample ppm is:
A. 0.6
B. 6.0
C. 60.0
D. 16.0
Solution
To solve the above problem we will use some basic concepts of chemistry. We know that ppm represents parts per million. Parts per million (ppm) is one of the measures of representing concentration. Here we have one kilogram (1Kg) of the seawater sample. So using the basic concepts of measurements we will calculate the concentration in parts per million (ppm).
Formula Used: Concentration in ppm=WsampleWsolute×106
Where Wsolute represents the amount of solute in (mg) and Wsample represents the mass of the sample in (mg).
Complete step by step answer:
First, we will understand the important measure of the concentration of parts per million (ppm). Parts per million is the way of representing the dilute concentration of substances. The measure of concentration is in order of (106). Now we will understand and extract the given quantities from the problem. We have given that One kilogram of seawater sample contains 6mg dissolved O2. So here we know that one kilogram of seawater sample corresponds to (106mg) of seawater sample which contains 6mg dissolvedO2.
Now here we have the given quantities as the amount of solute Wsolute=6mg and the amount of the mass of seawater sample is Wsample=1kg=106mg. Now we have all the required quantities to calculate the concentration of O2 the sample ppm. So, we will substitute the values in the formula.
Concentration in ppm=WsampleWsolute×106=106mg6mg×106=6.0
So, here the calculated value of concentration O2 in the sample ppm is 6.0.
So, the correct answer is Option B.
Note: The measure of concentration parts per million (ppm) is described as the concentration of something in water or soil. It also measures the mass of chemicals or contaminates per volume. It is equivalent to the fractional amount multiplied by one million.