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Question: One kg of a diatomic gas is at a pressure of 8 × 10<sup>4</sup> N/m<sup>2</sup>. The density of the ...

One kg of a diatomic gas is at a pressure of 8 × 104 N/m2. The density of the gas is 4 kg/m3. What is the energy of the gas due to its thermal motion ?

A

3 × 104 J

B

5 × 104 J

C

6 × 104 J

D

7 × 104 J

Answer

5 × 104 J

Explanation

Solution

E = f2\frac{f}{2}RTn**.**

Since gas is diatomic hence f = 5

E = 52\frac{5}{2} RTn (\becausePV = nRT)

E = 52\frac{5}{2}PV

E = 52\frac { 5 } { 2 } PMD(M=MassD=Density)\frac{PM}{D}\left( \begin{aligned} & M = Mass \\ & D = Density \end{aligned} \right)E = 52\frac{5}{2} × 8×104×14\frac{8 \times 10^{4} \times 1}{4} = 5 × 104 J.

So option (2 ) is correct.