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Question

Chemistry Question on Enthalpy change

One gram sample of NH4NO3NH _{4} NO _{3} is decomposed in a bomb calorimeter. The temperature of the calorimeter increases by 6.12K6.12\, K. The heat capacity of the system is 1.23kJ/g/deg1.23\, kJ / g / deg. What is the molar heat of decomposition for NH4NO3NH _{4} NO _{3} ?

A

7.53kJ/mol-7.53\, kJ / mol

B

398.1kJ/mol-398.1\, kJ / mol

C

16.1kJ/mol-16.1 \,kJ / mol

D

602kJ/mol-602\, kJ / mol

Answer

602kJ/mol-602\, kJ / mol

Explanation

Solution

Heat of decomposition, ΔE=msΔT\Delta E=m \cdot s \cdot \Delta T =1×1.23×6.12=7.5276kJ=1 \times 1.23 \times 6.12=7.5276\, kJ Molar heat of decomposition for NH4NO3NH _{4} NO _{3} =7.5276×80=602.2kJ=7.5276 \times 80=602.2 \,kJ