Question

One gram mole of a gas at NTP occupies $22.4\, L$. This fact was derived from

• A. law of gaseous volumes
• B. Avogadro's hypothesis
• C. Berzelius hypothesis
• D. Dalton's atomic theory

Answer 1

Answer: (B)

Avogadro's hypothesis

Answer 2

According to ideal gas equation, $P V=n R T$ Putting the standard conditions, i.e. $P =1$ atm $n=1$ mole, $R=0.0821\, L$ atm $K^{-1}$, mol $^{-1},$ $T=273\, K$ $V=\frac{n R T}{P}=\frac{1 \text { mole } \times 0.0821 L\,atm K^{-1} mol ^{-1} \times 273\, K }{1 atm }$ $V=22.4$