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Question: One gm metal \[{M^{3 + }}\] was discharged by the passage of \(1.81 \times {10^{23}}\) electrons. Wh...

One gm metal M3+{M^{3 + }} was discharged by the passage of 1.81×10231.81 \times {10^{23}} electrons. What is the atomic mass of the metal?
A) 8g/mol8g/mol
B) 9g/mol9g/mol
C) 10g/mol10g/mol
D) None of these

Explanation

Solution

The reaction is M3++3eM{M^{3 + }} + 3{e^ - } \to M. The charge on a single electron is 1.6×1019C1.6 \times {10^{ - 19}}C and the value of 1F1F is 96500C96500C. Also, we are given that the number of electrons is 1.81×10231.81 \times {10^{23}}.

Complete answer:
When we discharge one gm of M3+{M^{3 + }} , the reaction is
M3++3eM{M^{3 + }} + 3{e^ - } \to M
So, here, we can see that one mole of metal is deposited by 33 electrons, which means 3F3F.
So, one mole of metal is deposited by 3×96500C=289500C3 \times 96500C = 289500C
Now, the charge on a single electron is 1.6×1019C1.6 \times {10^{ - 19}}C
So, the charge on 1.81×10231.81 \times {10^{23}} electrons is (1.6×1019×1.81×1023)=2.9×104C\left( {1.6 \times {{10}^{ - 19}} \times 1.81 \times {{10}^{23}}} \right) = 2.9 \times {10^4}C
So, 289500C289500C deposit 11 mole of metal
So, 2.9×104C2.9 \times {10^4}C will deposit 2.9×104289500=29000289500=0.100\dfrac{{2.9 \times {{10}^4}}}{{289500}} = \dfrac{{29000}}{{289500}} = 0.100 moles of metal.
So, it is now clear that 0.1000.100 moles metal is equal to 11 gm metal
So, atomic mass of the metal is 1010 gm/mol
Hence option C is correct .

Additional information: The atomic mass of a single atom is defined simply as its total mass. It is generally expressed in “amu” (atomic mass units). For example, an atom of carbon, which has six neutrons (carbon-12), has an atomic mass of 12 amu. For any given isotope or atom or molecule, the sum of the numbers of protons and the number of neutrons in the nucleus is called the mass number of that isotope or atom or molecule. The reason behind it is that each proton and each neutron weigh one amu. So, one can calculate the mass of an atom only by adding together the number of protons and neutrons and then multiplying by 1 amu.

Note:
Here, FF is the unit, Faraday. It is used to measure the electricity, which is required to break down a compound by electrolysis and also the value of 1F1F is 96500C96500C [Where, CC is the unit, Coulomb]. The charge carried by one mole of electrons is about 9650096500 coulombs per mole.