One-fourth length of a spring of force constant k is cut awa... | Physics | SolveeIt | Solveeit

Today, August 24

Question

One-fourth length of a spring of force constant k is cut away. The force constant of the remaining spring will be

A

$\frac{3}{4}k$

B

$\frac{4}{3}k$

C

k

D

4k

Answer

$\frac{4}{3}k$

Explanation

Solution

By using $k ? \frac{1}{l}$ Since, one-fourth length is cut away so remaining length is $\frac{3}{4} th$ hence k becomes $\frac{4}{3}$ times ie, $k' = \frac{4}{3}k.$