Question

One-fourth length of a spring of force constant k is cut away. The force constant of the remaining spring will be

• A. $\frac{3}{4}k$
• B. $\frac{4}{3}k$
• C. k
• D. 4k

Answer 1

Answer: (B)

$\frac{4}{3}k$

Answer 2

$BY \, using \, k ? \frac{1}{l}$ Since, one-fourth length is cut away so remaining length is $\frac{3}{4}th$hence k becomes $\frac{4}{3}times \, i.e, k'=\frac{4}{3}k$