Question

One Faraday of electricity liberates $x×10^{−1 }$gram atom of copper from copper sulphate, x is ______.

Answer 1

$\text{Cu}^{2+} + 2e^- \rightarrow \text{Cu}$
$2 \, \text{Faraday} \rightarrow 1 \, \text{mol Cu}$
$1 \, \text{Faraday} \rightarrow 0.5 \, \text{mol Cu deposit}$
$0.5 \, \text{mol} = 0.5 \, \text{g atom} = 5 \times 10^{-1}$
$x = 5$

Answer 2

$\text{Cu}^{2+} + 2e^- \rightarrow \text{Cu}$
$2 \, \text{Faraday} \rightarrow 1 \, \text{mol Cu}$
$1 \, \text{Faraday} \rightarrow 0.5 \, \text{mol Cu deposit}$
$0.5 \, \text{mol} = 0.5 \, \text{g atom} = 5 \times 10^{-1}$
$x = 5$