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Question

Physics Question on laws of motion

One end of a string of length l'l' is connected to a particle of mass �m� and the other to a small peg on a smooth horizontal table. If the particle moves in a circle with speed �v�, the net force on the particle (directed towards the centre) is : (T is the tension in the string)

A

T

B

Tmv21T-\frac{mv^2}{1}

C

T+mv21T+\frac{mv^2}{1}

D

0

Answer

T

Explanation

Solution

When a particle connected to a string revolves in a circular path around a centre, the centripetal force is provided by the tension produced in the string. Hence, in the given case, the net force on the particle is the tension TT. (T=(mv2)/I)\left(T=\left( mv ^{2}\right) / I \right)