Question
Quantitative Aptitude Question on Time and Work
One day, Rahul started a work at 9 AM and Gautam joined him two hours later.They then worked together and completed the work at 5 PM the same day. If both had started at 9 AM and worked together, the work would have been completed 30 minutes earlier. Working alone, the time Rahul would have taken, in hours, to complete the work is
12
11.5
12.5
10
10
Solution
Let's denote the work rate of Rahul as R work/hour and the work rate of Gautam as G work/hour.
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When both started together at 9 AM:
The total time they worked together was 8 hours (from 9 AM to 5 PM). They would have finished the work in 7.5 hours (30 minutes earlier). So, their combined work rate when they started together would be:
Total Work=(R+G)×7.5 -
On the day Rahul started at 9 AM and Gautam joined him 2 hours later:
Rahul worked for 2 hours alone, and then they worked together for the next 6 hours (from 11 AM to 5 PM). This gives:
Total Work=2R+6(R+G)
Since the total work done in both scenarios is the same, we can equate the two expressions:
2R+6(R+G)=7.5(R+G)
Expanding and simplifying:
2R+6R+6G=7.5R+7.5G
8R+6G=7.5R+7.5G
0.5R=1.5G
R=3G
Now, let's use the combined work rate from the first scenario:
Total Work=(R+G)×7.5
Using the relationship R=3G, we get:
Total Work=(3G+G)×7.5
Total Work=4G×7.5
Total Work=30G
Now, using this total work with Rahul's individual work rate for the time he worked alone:
2R=2(3G)=6G
Subtracting this from the total work to get the work done by both together:
30G−6G=24G
This means that both of them, working together for 6 hours, did 24G of the work:
6(R+G)=24G Using R=3G:
6(4G)=24G
The relationship holds true.
Now, to find the time Rahul would take to complete the entire work by himself:
Using R=3G:
Total Work=30G
If Rahul does the entire work:
Time for Rahul=RTotal Work=3G30G=10 hours
Rahul would take 10 hours to complete the work by himself.