Question

One coulomb of charge passes through solution of AgNO3 and CuSO4 connected in series and the conc. of two solution being in the ratio 1 : 2. The ratio of weight of Ag and Cu deposited on Pt electrode is.

• A. 107.9 : 63.54
• B. 54 : 31.77
• C.
  107. 9 : 31.77
• D. 54 : 63.54

Answer 1

Answer: (C)

107. 9 : 31.77

Answer 2

Faradays’s IInd Law $\frac{W}{E} = cons\tan t$

So, $\frac{W_{Ag}}{E_{Ag}} = \frac{W_{Cu}}{E_{Cu}}(Ag^{+} + e^{-}\overset{\quad\quad}{\rightarrow}Ag,E_{Ag} = \frac{M}{1})$

$\therefore\frac{W_{Ag}}{W_{Cu}} = \frac{E_{Ag}}{E_{Cu}} = \frac{107.9}{63.54/2}$

$(Cu^{+ 2} + 2e^{-} \rightarrow Cu,E_{cu} = \frac{M}{2})$

$= \frac { 107.9 } { 31.77 }$