Question

One card is drawn from each of two ordinary packs of 52 cards. The probability that at least one of them is an ace of heart, is

• A. $\frac { 103 } { 2704 }$
• B. $\frac { 1 } { 2704 }$
• C. $\frac { 2 } { 52 }$
• D. $\frac { 2601 } { 2704 }$

Answer 1

Answer: (A)

$\frac { 103 } { 2704 }$

Answer 2

Required probability is $1 - P$ (no ace of heart)

$= 1 - \frac { 51 } { 52 } \cdot \frac { 51 } { 52 } = \frac { ( 52 + 51 ) } { 52.52 } = \frac { 103 } { 2704 }$