Solveeit Logo

Question

Chemistry Question on Aldehydes, Ketones and Carboxylic Acids

On treatment of propanone with dilute Ba(OH)2Ba(OH)_2, the product formed is

A

aldol

B

phorone

C

propionaldehyde

D

4-hydroxy-4-methyl-2-pentanone

Answer

4-hydroxy-4-methyl-2-pentanone

Explanation

Solution

In the presence of Ba(OH)2Ba ( OH )_{2}, propanone (acetone) undergoes aldol type condensation as