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Chemistry Question on Werner’s Theory of Coordination Compounds

On treatment of 100 mL100\, mL of 0.1 M0.1\, M solution of CoCl3⋅6H2OCoCl _{3} \cdot 6 H _{2} O with excess AgNO3;1.2×1022AgNO _{3} ; 1.2 \times 10^{22} ions are precipitated. The complex is

A

[Co(H2O)6]Cl3\left[ Co \left( H _{2} O \right)_{6}\right] Cl _{3}

B

[Co(H2O)5Cl]Cl2⋅H2O\left[ Co \left( H _{2} O \right)_{5} Cl \right] Cl _{2} \cdot H _{2} O

C

[Co(H2O)4Cl2]Cl⋅2H2O\left[ Co \left( H _{2} O \right)_{4} Cl _{2}\right] Cl \cdot 2 H _{2} O

D

[Co(H2O)3Cl3]⋅3H2O\left[ Co \left( H _{2} O \right)_{3} Cl _{3}\right] \cdot 3 H _{2} O

Answer

[Co(H2O)5Cl]Cl2⋅H2O\left[ Co \left( H _{2} O \right)_{5} Cl \right] Cl _{2} \cdot H _{2} O

Explanation

Solution

Millimoles of AgNO3=1.2×10226×1023×1000=20AgNO _{3}=\frac{1.2 \times 10^{22}}{6 \times 10^{23}} \times 1000=20 Millimoles of CoCl3⋅6H2O=0.1×100=10CoCl _{3} \cdot 6 H _{2} O =0.1 \times 100=10 ∴\therefore Each mole of CoCl3⋅6H2OCoCl _{3} \cdot 6 H _{2} O gives two chloride ions. ∴[Co(H2O)5Cl]Cl2⋅H2O\therefore\left[ Co \left( H _{2} O \right)_{5} Cl \right] Cl _{2} \cdot H _{2} O