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Question: On treating a mixture of two alkyl halides with sodium metal in dry ether, 2-methyl propane was obta...

On treating a mixture of two alkyl halides with sodium metal in dry ether, 2-methyl propane was obtained. The alkyl halides are.

A

2-chloropropane and chloromethane

B

2-chloropropane and chloroethane

C

Chloromethane and chloroethane

D

Chloromethane and 1-chloropropane

Answer

2-chloropropane and chloromethane

Explanation

Solution

It is Wurtz reaction in which hydrocarbon formed when alkyl halide react with Na metal in dry ether.

& \text{chloro} \\ & \text{methane} \end{aligned}}{CH_{3}Cl} + 2Na\overset{\quad\text{ether}\quad}{\rightarrow}$$ $$\underset{\text{2 methyl propane}}{CH_{3} - \overset{CH_{3}\mspace{6mu}}{\overset{|}{C} ⥂ H -}CH_{3} + 2NaCl}$$