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Question

Physics Question on Inclined planes

On the horizontal surface of a truck a block of mass 1 kg is placed (μ=0.6)(\mu = 0.6) and truck is moving with acceleration 5m/sec25 m/sec^2 then the frictional force on the block will be

A

5 N

B

6 N

C

5.88 N

D

8 N

Answer

5 N

Explanation

Solution

frl=μsN=μs×mg=0.6×1×10=6N.f_{rl}=\mu_sN=\mu_s\times mg=0.6\times1\times10=6 N. where frlf_{rl} is the force of limiting friction. Pseudo force =ma=1×5;F=5N=ma = 1\times 5 ; F = 5\, N If F<frlF < f_{rl}, block does not move. So static friction is present. Static friction = applied force . fr=5N\therefore f_r=5\, N.