Question

On the electrolysis of aqueous solution of sodium sulphate, on cathode we get.

• A. $ightarrow$
• A. (d) $ightarrow$
• B. $ightarrow$
• C. $ightarrow$

Answer 1

Answer: (B)

$ightarrow$

Answer 2

Water is reduced at the cathode and oxidized at the anode instead of $Na^{+}$and $SO_{4}^{2 -}$.

Cathode : $2H_{2}O + 2e^{-} \rightarrow H_{2} + 2OH^{-}$

Anode : $H_{2}O \rightarrow 2H^{+} + \frac{1}{2}O_{2} + 2e^{-}$.