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Question: On the basis of thermo chemical equations (i), (ii) and (iii), find out which of the algebraic relat...

On the basis of thermo chemical equations (i), (ii) and (iii), find out which of the algebraic relationships given in options (1) to (4) is correct.

(i) C(graphite)+O2(g)→CO2(g);ΔrH=xkJmol−1C_{(graphite)} + O_{2(g)} \rightarrow CO_{2(g)};\Delta_{r}H = xkJmol^{- 1}

(ii) C(graphite)+12O2(g)→CO(g);ΔrH=ykJmol−1C_{(graphite)} + \frac{1}{2}O_{2(g)} \rightarrow CO_{(g)};\Delta_{r}H = ykJmol^{- 1}

(iii) CO(g)+12O2(g)→CO2(g);ΔrH=zkJmol−1CO_{(g)} + \frac{1}{2}O_{2(g)} \rightarrow CO_{2(g)};\Delta_{r}H = zkJmol^{- 1}

A

z = x + y

B

x = y – z

C

x = y + z

D

y = 2z – x

Answer

x = y + z

Explanation

Solution

: C(graphite)+O2(g)→CO2(g);ΔrH=xkJmol−1C_{(graphite)} + O_{2(g)} \rightarrow CO_{2(g)};\Delta_{r}H = xkJmol^{- 1} …(i)

C(graphite)+12O2(g)→CO(g);ΔrH=ykJmol−1C_{(graphite)} + \frac{1}{2}O_{2(g)} \rightarrow CO_{(g)};\Delta_{r}H = ykJmol^{- 1} …(ii)

By substracting eqn (ii) from (i), we get

CO(g)+12O2(g)→CO2(g);ΔrH=zkJmol−1CO_{(g)} + \frac{1}{2}O_{2(g)} \rightarrow CO_{2(g)};\Delta_{r}H = zkJmol^{- 1}….(iii)

Thus, x – y = z i.e., x = y + z