Question
Question: On reacting \(Mn{O_2}\) with \(HCl\) , 1\. \(M{n^{4 + }}\) is reduced to 2\. \(C{l^ - }\) is oxi...
On reacting MnO2 with HCl ,
1. Mn4+ is reduced to
2. Cl− is oxidised to
A) Mn3+,Cl4+
B) Mn2+,Cl
C) Mn,Cl
D) Mn is not reduced nor Cl is oxidised
Solution
Reaction of MnO2 with HCl is a redox reaction. The reactions in which both oxidation ( loss of electrons) and reduction (gain of electrons) occur simultaneously are termed as redox reactions. First, write the balanced redox reaction of MnO2 with HCl, and then find the reduced and oxidised species.
Complete step by step answer:
Redox reaction of MnO2 with HCl:
MnO2+4HCl→MnCl2+2H2O+Cl2
1.) In the above reaction, MnO2 is converting to MnCl2. Now, the oxidation state of Mn in MnO2 is +4 and the oxidation state of Mn in MnCl2 is +2 . Therefore, Mn+4 is changing to Mn+2 from going left to right. Since, reduction is the gain of electrons or decrease in the oxidation state of an element, Mn is undergoing reduction in the given reaction. Thus, Mn+4 is reduced to Mn+2.
Reduction half reaction: MnO2+2e−→MnCl2
2.) On going from left to right in the redox reaction of MnO2 with HCl, HClis converted to Cl2. Oxidation state of chlorine in HCl is −1 while the oxidation state of chlorine in Cl2 is zero. Since, oxidation is the loss of electrons or increase in the oxidation number of an element, HCl is oxidised here to Cl2 or we can say, Cl− ion is oxidised to Cl.
Oxidation half reaction: 2Cl−→Cl2+2e−
Thus, correct option is B, that is, Mn2+,Cl because Mn+4is reduced to Mn+2 and Cl− ion is oxidised to Cl on reacting MnO2 with HCl .
So, the correct answer is “Option B”.
Note: Oxidising agent is an acceptor of electrons while reducing agent is a donor of electrons. In reduction half reaction, manganese is reduced, therefore it acts as an oxidising agent because it accepts electrons. In the oxidation half reaction, chlorine is oxidised and acts as a reducing agent for manganese because it donates electrons to manganese.