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Question: On reacting \(Mn{O_2}\) with \(HCl\) , 1\. \(M{n^{4 + }}\) is reduced to 2\. \(C{l^ - }\) is oxi...

On reacting MnO2Mn{O_2} with HClHCl ,
1. Mn4+M{n^{4 + }} is reduced to
2. ClC{l^ - } is oxidised to

A) Mn3+,Cl4+M{n^{3 + }},C{l^{4 + }}
B) Mn2+,ClM{n^{2 + }},Cl
C) Mn,ClMn,Cl
D) MnMn is not reduced nor ClCl is oxidised

Explanation

Solution

Reaction of MnO2Mn{O_2} with HClHCl is a redox reaction. The reactions in which both oxidation ( loss of electrons) and reduction (gain of electrons) occur simultaneously are termed as redox reactions. First, write the balanced redox reaction of MnO2Mn{O_2} with HClHCl, and then find the reduced and oxidised species.

Complete step by step answer:
Redox reaction of MnO2Mn{O_2} with HClHCl:
MnO2+4HClMnCl2+2H2O+Cl2Mn{O_2} + 4HCl \to MnC{l_2} + 2{H_2}O + C{l_2}

1.) In the above reaction, MnO2Mn{O_2} is converting to MnCl2MnC{l_2}. Now, the oxidation state of MnMn in MnO2Mn{O_2} is +4 + 4 and the oxidation state of MnMn in MnCl2MnC{l_2} is +2 + 2 . Therefore, Mn+4M{n^{ + 4}} is changing to Mn+2M{n^{ + 2}} from going left to right. Since, reduction is the gain of electrons or decrease in the oxidation state of an element, MnMn is undergoing reduction in the given reaction. Thus, Mn+4M{n^{ + 4}} is reduced to Mn+2M{n^{ + 2}}.
Reduction half reaction: MnO2+2eMnCl2Mn{O_2} + 2{e^ - } \to MnC{l_2}

2.) On going from left to right in the redox reaction of MnO2Mn{O_2} with HClHCl, HClHClis converted to Cl2C{l_2}. Oxidation state of chlorine in HClHCl is 1 - 1 while the oxidation state of chlorine in Cl2C{l_2} is zero. Since, oxidation is the loss of electrons or increase in the oxidation number of an element, HClHCl is oxidised here to Cl2C{l_2} or we can say, ClC{l^ - } ion is oxidised to ClCl.

Oxidation half reaction: 2ClCl2+2e2C{l^ - } \to C{l_2} + 2{e^ - }
Thus, correct option is B, that is, Mn2+,ClM{n^{2 + }},Cl because Mn+4M{n^{ + 4}}is reduced to Mn+2M{n^{ + 2}} and ClC{l^ - } ion is oxidised to ClCl on reacting MnO2Mn{O_2} with HClHCl .
So, the correct answer is “Option B”.

Note: Oxidising agent is an acceptor of electrons while reducing agent is a donor of electrons. In reduction half reaction, manganese is reduced, therefore it acts as an oxidising agent because it accepts electrons. In the oxidation half reaction, chlorine is oxidised and acts as a reducing agent for manganese because it donates electrons to manganese.