Question

On passing 3 ampere of electricity for 50 minutes,1.8 g of metal deposits. The equivalent mass ofmetal is

• A. 20.5
• B. 25.8
• C. 19.3
• D. 30.7.

Answer 1

Answer: (C)

19.3

Answer 2

$Q = It = 3\,amp \times 50\times 60$ sec $= 9000\,C$ $9000\,C$ of electricity deposits metal $= 1.8\,gm$ $96500\,C$ of electricity deposits metal $= \frac{1.8}{9000} \times 96500 = 19.3\,gm$