Solveeit Logo
Login

Question

Question: On passing 0.5 faraday of electricity through \(H_{2}\), the amount of \(H^{+}\) deposited on cathod...

On passing 0.5 faraday of electricity through H2H_{2}, the amount of H+H^{+} deposited on cathode is.

A

35.5 gm

B

17.75 gm

C

71 gm

D

142 gm

Answer

17.75 gm

Explanation

Solution

Equivalent of Cl deposited

= No. of Faraday passed = 0.5

Wt. of Cl=0.5×Eq.wt.=0.5×35.5=17.75gmCl = 0.5 \times Eq.wt. = 0.5 \times 35.5 = 17.75gm.