Question

On heating ozone its volume:
(A) increases to $1\dfrac{1}{2}$times
(B) decreases to half
(C) remains unchanged
(D) becomes double

Answer 1

In order to answer the given question, we must know about the product formed on heating of ozone molecules. We must balance the entire equation which is obtained. We can make use of the principle of atom conservation in order to find the volume obtained after heating ozone.

Complete answer:
Let us first see what will happen when the ozone molecule is heated. The reaction of heating of ozone is given below:
${O_3}\xrightarrow{\Delta }{O_2} + [O]$
On heating 1 mole of ozone, we would be getting 1 mole of oxygen molecule and 1 mole of the oxygen atom. This oxygen atom is nascent oxygen which is highly unstable. So, if we are considering ozone molecules to be around 1 litre, then the product obtained, i.e. the oxygen molecule will also be 1 litre and the nascent oxygen will be around 0.5 litre. This is because the Nascent oxygen is only half of the oxygen molecule. In order to find the volume obtained, we can compare the volume of the reactant and the products. From the above discussion, we can see that the total volume of the product produced is around 1.5 litres. Therefore, the volume is increased to $1\dfrac{1}{2}$ times.

Hence the correct answer is option (A).

Note:
Let us now remember some of the characteristics of ozone.
- Ozone is inorganic molecule
- Molecular formula of ${O_3}$
- Pale blue gas
- Have a pungent odour
- Allotrope of the oxygen.