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Question: On heating \(CHCl_{3}\) with aq. NaOH, the product is....

On heating CHCl3CHCl_{3} with aq. NaOH, the product is.

A

CH3COONaCH_{3}COONa

B

HCOONaHCOONa

C

Sodium oxalate

D

CH3OHCH_{3}OH

Answer

HCOONaHCOONa

Explanation

Solution

HCOOH→−H2ONaOHHCOONa\mathrm { HCOOH } \xrightarrow [ - \mathrm { H } _ { 2 } \mathrm { O } ] { \mathrm { NaOH } } \mathrm { HCOONa }