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Question: On folding, a resistance wire of \(8\Omega \) doubles up. Find the new resistance of the wire. A) ...

On folding, a resistance wire of 8Ω8\Omega doubles up. Find the new resistance of the wire.
A) 0.5Ω0.5\Omega
B) 1.5Ω1.5\Omega
C) 2Ω2\Omega
D) 4Ω4\Omega

Explanation

Solution

On folding, the resistance wire doubled up. This implies that the length of the wire got reduced to its half and the area of the wire doubled.

Formulas used:
The resistance of a wire of length ll and area AA is given by, R=ρlAR = \dfrac{{\rho l}}{A} where ρ\rho is the resistivity of the material used to make the wire.

Complete step by step answer:
Step 1: List the data given in the question.
The resistance of the wire before folding is R=8ΩR = 8\Omega .
Let ll be the length, AA be the area of cross-section of the wire and ρ\rho be the resistivity of the material of the wire.
We have the expression for the resistance of the wire, R=ρlAR = \dfrac{{\rho l}}{A} --------- (1).

Step 2: Express the new resistance of the wire on folding.
On folding the new length of the wire becomes half of its original value i.e., l=l2l' = \dfrac{l}{2} and the new area of cross-section of the wire will be double of the original cross-sectional area i.e., A=2AA' = 2A.
Now the new resistance RR' can be expressed in terms of its new length and new area as R=ρlAR' = \dfrac{{\rho l'}}{{A'}}.
Substituting l=l2l' = \dfrac{l}{2} and A=2AA' = 2A in the above equation we get, R=ρ(l2)2AR' = \dfrac{{\rho \left( {\dfrac{l}{2}} \right)}}{{2A}}.
Reducing the above equation we get, R=ρl4AR' = \dfrac{{\rho l}}{{4A}} -------- (2).

Step 3: Using equations (1) and (2) find the value of the new resistance.
Equation (1) gives R=ρlAR = \dfrac{{\rho l}}{A} and equation (2) gives R=ρl4AR' = \dfrac{{\rho l}}{{4A}}.
Substituting equation (1) in equation (2) we get, R=R4R' = \dfrac{R}{4} .
Given, R=8ΩR = 8\Omega . Then new resistance will be R=84=2ΩR' = \dfrac{8}{4} = 2\Omega .

Therefore, the new resistance is 2Ω2\Omega .

Note:
On folding the resistance wire, only the dimensions of the wire change, i.e., the length and area of the wire change. The resistivity is a property of the material of the wire. It refers to the ability of the material to conduct electricity. Thus the resistivity remains constant on folding the wire but changes if you change the material of the wire.