Question

On dipping one end of a capillary in liquid and inclining the capillary at an angles $30^{o}$ and $60^{o}$ with the vertical, the lengths of liquid columns in it are found to be $l_{1}$ and $l_{2}$ respectively. The ratio of $l_{1}$ and $l_{2}$ is

• A. $1:\sqrt{3}$
• B. $1:\sqrt{2}$
• C. $\sqrt{2}:1$
• D. $\sqrt{3}:1$

Answer 1

Answer: (A)

$1:\sqrt{3}$

Answer 2

$l_{1} = \frac{h}{\cos\alpha_{1}}$ and

$\therefore\frac{l_{1}}{l_{2}} = \frac{\cos\alpha_{2}}{\cos\alpha_{1}} = \frac{\cos 60^{o}}{\cos 30^{o}} = \frac{1/2}{\sqrt{3}/2}$= $1:\sqrt{3}$