Question

On complete combustion of 0.492 g of an organic compound containing C, H and O, 0.7938 g of CO2 and 0.4428 g of H2O was produced. The % composition of oxygen in the compound is _______.

Answer 1

Mole of CO2=Moles of C=$\frac{0.793}{44}$

Weight of 'C'=$\frac{0.793}{44}$×12=0.216gm

Moles of 'H' =$\frac{0.442}{18}$×2

Weight of 'H' =$\frac{0.442}{18}$×2×1=0.049gm

∴ Weight of ‘O’ =0.492−0.216−0.049=0.227gm

% of 'O' =$\frac{0.227}{0.492}$×100=46.13%