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Question: On catalytic reduction \(\text{(}{{\text{H}}_{\text{2}}}\text{/Pd)}\) how many alkenes will give \(\...

On catalytic reduction (H2/Pd)\text{(}{{\text{H}}_{\text{2}}}\text{/Pd)} how many alkenes will give 2-methyl butane\text{2-methyl butane}?
(A)11
(B)22
(C)33
(D)44

Explanation

Solution

The process which involves gain of electrons (or hydrogen atom) by an atom or molecule is called reduction.
Catalytic hydrogenation of alkene is an electrophilic addition reaction.

Complete answer:
The substance which donates electrons in chemical reactions is called reducing agent. There are many reducing organic compounds like(H2/Pd)\text{(}{{\text{H}}_{\text{2}}}\text{/Pd)}, LiAlH4,NaBH4\text{LiAl}{{\text{H}}_{\text{4}}}\text{,}\,\text{NaB}{{\text{H}}_{\text{4}}}which causes reduction of organic compounds like alkene, and other carboxy compounds.

In catalytic hydrogenation alkene get reduced to alkenes with the help of H2{{\text{H}}_{\text{2}}}in the presence of metal like platinum (Pt.), palladium (Pd), nickel (Ni) or rhodium (Rh).
In this reaction new sigma(C-H)\text{(C-H)}bonds are formed. In this reaction a hydrogen atom takes place in alkene.
This reaction also forms an experimental basis of heat of hydrogenation which is used to explain the stability of isomeric alkenes. Alkynes are less reactive to catalytic hydrogenation in respect to alkene, because of the presence of stronger pi bond.
Catalytic hydrogenation of alkenes takes place in three steps –
(i) absorption of hydrogen gas on the metal surface. In the presence of catalyst cleavage of H2{{\text{H}}_{\text{2}}} takes place and each hydrogen atom forms attachment with the metal ion.
(ii) alkene shows an approach toward the hydrogen atom on the metal surface. Metal catalysts attract the alkene and transfer hydrogen atoms to the alkene.
(iii) Alkene reacts with the H-atom and gets reduced by forming two new C-H\text{C-H} bonds.
Two alkene molecules 2-methyl-2-butene\text{2-methyl-2-}\,\,\text{butene} and 2-methyl-1-butene\text{2-methyl-1-}\,\,\text{butene} gives 2-methyl butane\text{2-methyl butane} after catalytic hydrogenation.

So, option (B) is the correct option.

Note
(H2/Pd)\text{(}{{\text{H}}_{\text{2}}}\text{/Pd)} acts as a weak reducing agent. It reduces alkene, aldehyde and ketone but cannot reduce the carboxylic acid, ester and amides. It reduces aldehyde and ketones into corresponding alcohols.