Question

On bombarding $U^{235}$ by slow neutron, $200\, MeV$ energy is released. If the power output of atomic reactor is $1.6\, MW$, then the rate of fission will be

• A. $5\times10 ^{22}/s$
• B. $5\times10 ^{16}/s$
• C. $8\times10 ^{16}/s$
• D. $20\times10 ^{16}/s$

Answer 1

Answer: (B)

$5\times10 ^{16}/s$

Answer 2

Energy released on bombarding $U ^{235}$ by neutron
$=200 \,MeV$
Power output of atomic reactor $=1.6 \,MW$
$\therefore$ Rate of fission $=\frac{1.6 \times 10^{6}}{200 \times 10^{6} \times 1.6 \times 10^{-19}}$
$=5 \times 10^{16} / s$