Question

On a rough horizontal surface, a body of mass 2 kg is given a velocity of 10 m/s. If the coefficient of friction is 0.2 and $g = 10 \mathrm {~m} / \mathrm { s } ^ { 2 }$ , the body will stop after covering a distance of

• A. 10 m
• B. 25 m
• C. 50 m
• D. 250 m

Answer 1

Answer: (B)

25 m

Answer 2

$S = \frac { u ^ { 2 } } { 2 \mu g } = \frac { ( 10 ) ^ { 2 } } { 2 \times 0.2 \times 10 } = 25 \mathrm {~m}$