Question

On a rough horizontal surface, a body of mass 2 kg is given a velocity of 10 m/s. If the coefficient of friction is 0.2 and g = 10 ms^–2, the body will stop after covering a distance of –

• A. 10 m
• B. 25 m
• C. 50 m
• D. 250 m

Answer 1

Answer: (B)

25 m

Answer 2

u = 10, v = 0, a = – mg

Now v² = u² + 2as