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Question

Physics Question on Ray optics and optical instruments

On a hypotenuse of a right prism (306090)\left(30^{\circ}-60^{\circ}-90^{\circ}\right) of refractive index 1.501.50, a drop of liquid is placed as shown in figure. Light is allowed to fall normally on the short face of the prism. In order that the ray of light may get totally reflected, the maximum value of refractive index is :

A

1.3

B

1.47

C

1.2

D

1.25

Answer

1.3

Explanation

Solution

for total internal infliction By snells low sin60sin90=Mliquid1.50\frac{\sin 60}{\sin 90} = \frac{M_{\text{liquid}}}{1.50} 32×32=Mliquide\frac{\sqrt{3}}{2}\times \frac{3}{2} = M_{\text{liquide}} Mliquide=1.29=1.3M_{\text{liquide}} = 1.29 = 1.3