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Question

Physics Question on Motion in a plane

Of the vectors given below, the parallel vectors are, A=6i^+8j^ A = 6 \hat i + 8 \hat j 30mmB=210i^+280k^30mm B = 210 \hat i + 280 \hat k C=0.3i^+0.4j^ C = 0.3 \hat i + 0.4 \hat j D=3.6i^+6j^+4.8k^ D = 3.6 \hat i + 6 \hat j + 4.8 \hat k

A

A and B

B

A and C

C

A and D

D

C and D

Answer

A and C

Explanation

Solution

A=6i^+8j^ A = 6 \hat i + 8 \hat j B=210i^+280k^ B = 210 \hat i + 280 \hat k C=0.3i^+0.4j^=120(6i^+8j^) C = 0.3 \hat i + 0.4 \hat j = \frac{1}{20} (6 \hat i + 8 \hat j) and \hspace30mm D = 3.6 \hat i + 6 \hat j + 4.8 \hat k Hence, it is clear that A and C are parallel and we can write as C=120A C = \frac{1}{20} A This implies that A is parallel to C.