Question: The third virial coefficient of a He gas is $4 \times 10^{-2}$ (lit/mol)$^2$. What will be volume of...

Question

The third virial coefficient of a He gas is $4 \times 10^{-2}$ (lit/mol) $^2$ . What will be volume of 2 mole He gas at 1 atm and 273K (273K > $T_B$ )

Answer 1

Solution

The virial equation of state is used, assuming the second virial coefficient ( $B$ ) is zero as it's not provided. The ideal gas volume is calculated first. Then, the third virial coefficient ( $C$ ) is used to correct the ideal volume using an iterative approximation. The calculated corrected volume is found to be approximately 44.8265 L, which is closest to the ideal gas volume, indicating a minimal deviation due to the small value of $C$ .