Question

Of the isomeric hexanes, the isomers that give the minimum and maximum number of monochloro derivatives are respectively

• A. $3$-methylpentane and $2,3$-dimethylbutane
• B. $2, 3$-dimethylbutane and $n$-hexane
• C. $2, 2$-dimethylbutane and $2$-methylpentane
• D. $2, 3$-dimethylbutane and $2$-methylpentane

Answer 1

Answer: (D)

$2, 3$-dimethylbutane and $2$-methylpentane

Answer 2

The possible isomers of hexane are undefinedundefined Out of these structure (iii) and (i) have respectively minimum and maximum number of monochloroderivatives For structure (iii), [Only 2 monochloroderivatives (minimum) are possible] For structure (i), [5 monochloroderivatives (maximum) are possible]