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Question

Mathematics Question on Some More Interesting Patterns

Observe the following pattern and find the missing digits.
11211^2 = 121121
1012101^2 = 1020110201
10012=10020011001^2 = 1002001
1000012=121100001^2 = 1…2…1
100000012=10000001^2 = …

Answer

In the given pattern, it can be observed that the squares of the given numbers have the same number of zeroes before and after the digit 22 as it was in the original number.
Therefore,
1000012=10000200001100001^2 = 10000200001
100000012=10000002000000110000001^2= 100000020000001