Question

The voltage across a pure inductor is represented in figure. Which one of the following curves in the figure will represent the current?

• A. Frequency
• B. Frequency
• C. Frequency
• D. Frequency

Answer 1

Answer: (A)

The question as stated has a mismatch with the options provided. Assuming the question implicitly asks for the graph of reactance versus frequency for a pure inductor, the correct option is (a).

Answer 2

For a pure inductor, the inductive reactance ($X_L$) is given by the formula:

$X_L = \omega L$

where $\omega$ is the angular frequency and $L$ is the inductance. Since $\omega = 2\pi f$, where $f$ is the linear frequency, the formula becomes:

$X_L = 2\pi f L$

This equation shows that the inductive reactance ($X_L$) is directly proportional to the frequency ($f$). A graph representing direct proportionality is a straight line passing through the origin with a positive slope. Therefore, graph (a) correctly represents the reactance of a pure inductor as a function of frequency.