Question

O is the circumcentre of the triangle ABC and R₁, R₂, R₃ are the radii of the circumcircles of the triangles OBC, OCA and OAB respectively. Then is equal to-

• A. $\frac { \mathrm { abc } } { \mathrm { R } }$
• B.
• C. $\frac { a + b + c } { R }$
• D.

Answer 1

Answer: (B)

Answer 2

We know that R =

D₁ = Area of D OBC

[D₂ = Area of DOCA, D₃ = area of DOAB]

R₁ = $\frac { \mathrm { aRR } } { 4 \Delta _ { 1 } }$ Ž $\frac { \mathrm { a } } { \mathrm { R } _ { 1 } }$ = $\frac { 4 \Delta _ { 1 } } { \mathrm { R } ^ { 2 } }$

Similarly, $\frac { \mathrm { b } } { \mathrm { R } _ { 2 } }$ = , =

\ $\frac { \mathrm { a } } { \mathrm { R } _ { 1 } }$++ = (D₁ + D₂ + D₃)

= = =.