Question

Numerically greatest term in expansion of (3 – 5x)¹¹ at x = $\frac{1}{5}$ is –

• A. (55).3⁹
• B. (55) .3⁸
• C. (55).3¹⁰
• D. None

Answer 1

Answer: (A)

(55).3⁹

Answer 2

Calculate = $\frac{(11 + 1).|5.\frac{1}{5}|}{|3| + |5.\frac{1}{5}|}$ = $\frac{12 \times 1}{4}$ = 3

T₃, T₄ are numerically greatest = ¹¹C₂ . (3)⁹. (1)²

= $\frac{11 \times 10}{2}$. (3)⁹ = (55). (3)⁹