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Chemistry Question on Chemical bonding and molecular structure

Number of unpaired electron in highest occupied molecular orbital of following species is :

A

N2−0,N2⊕−1,O2−2,O2⊕−2N_{2}-0, N_{2}^{⊕}-1, O_{2}-2, O_{2}^{⊕}-2

B

N2−1,N2⊕−0,O2−1,O2⊕−2N_{2}-1, N_{2}^{⊕}-0, O_{2}-1, O_{2}^{⊕}-2

C

N2−2,N2⊕−2,O2−0,O2⊕−2N_{2}-2, N_{2}^{⊕}-2, O_{2}-0, O_{2}^{⊕}-2

D

N2−1,N2⊕−1,O2−1,O2⊕−0N_{2}-1, N_{2}^{⊕}-1, O_{2}-1, O_{2}^{⊕}-0

Answer

N2−0,N2⊕−1,O2−2,O2⊕−2N_{2}-0, N_{2}^{⊕}-1, O_{2}-2, O_{2}^{⊕}-2

Explanation

Solution

N2→σ1s2,σ∗1s2,σ2s2,σ∗2s2,[π2px2=π2py2]σ2pz2⏟HOMON_{2} → σ1s^{2}, σ^{*}1s^{2}, σ2s^{2}, σ^{*}2s^{2}, [π2p_{x}^{2} = π2p_{y}^{2}] \underbrace{σ2p_{z}^{2}}_{HOMO}

N2⊕→σ1s2,σ∗1s2,σ2s2,σ∗2s2,[π2px2=π2py2]σ2pz1⏟HOMON_2^⊕ → σ1s^2, σ^*1s^2, σ2s^2, σ^*2s^2, [π2p_x^2 = π2p_y^2] \underbrace{σ2p_z^1}_{HOMO}

O2→σ1s2,σ∗1s2,σ2s2,σ∗2s2,[π2px2=π2py2][π∗2px1=π∗2py1]⏟HOMOO_2 → σ1s^2, σ^*1s^2, σ2s^2, σ^*2s^2, [π2p_x^2 = π2p_y^2] \underbrace{[π^*2p_x^1 = π^*2p_y^1]}_{HOMO}

O2⊕→σ1s2,σ∗1s2,σ2s2,σ∗2s2,[π2px2=π2py2][π∗2px1=π∗2py0]⏟HOMOO_2^⊕ → σ1s^2, σ^*1s^2, σ2s^2, σ*2s^2, [π2p_x^2 = π2p_y^2] \underbrace{[π^*2p_x^1 = π^*2p_y^0]}_{HOMO}

The correct option is (A): N2−0,N2⊕−1,O2−2,O2⊕−2N_{2}-0, N_{2}^{⊕}-1, O_{2}-2, O_{2}^{⊕}-2