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Question: Number of stereoisomers possible for the complexes, $[CrCl_3(py)_3]$ and $[CrCl_2(ox)_2]^{3-}$ are r...

Number of stereoisomers possible for the complexes, [CrCl3(py)3][CrCl_3(py)_3] and [CrCl2(ox)2]3−[CrCl_2(ox)_2]^{3-} are respectively

A

3 & 3

B

2 & 2

C

2 & 3

D

1 & 2

Answer

2 & 3

Explanation

Solution

For [CrCl3(py)3][CrCl_3(py)_3] (MA3_3B3_3 type), there are two geometrical isomers: facial (fac) and meridional (mer). Both are achiral, giving 2 stereoisomers. For [CrCl2(ox)2]3−[CrCl_2(ox)_2]^{3-} (MA2_2B2_2 type, B is bidentate), there are two geometrical isomers: trans-Cl and cis-Cl. The trans-Cl isomer is achiral. The cis-Cl isomer is chiral and exists as a pair of enantiomers. Thus, there are 1 (trans) + 2 (cis) = 3 stereoisomers.