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Question

Mathematics Question on Trigonometric Equations

Number of solutions of equation sin9θ=sinθ\sin 9 \theta=\sin \theta in the interval [0,2π][0,2 \pi] is

A

16

B

17

C

18

D

15

Answer

17

Explanation

Solution

sin9θ=sinθ\sin 9 \theta=\sin \theta 9θ=nπ+(1)nθ\Rightarrow 9 \theta=n \pi+(-1)^{n} \theta If n=2mn=2 m then 9θ=2mπ+θ9 \theta=2 m \pi+\theta θ=mπ4\Rightarrow \theta=\frac{m \pi}{4} If n=2m+1n=2 m+1 then 9θ=(2m+1)π=θ9 \theta=(2 m+1) \pi=-\theta θ=(2m+1)π10\Rightarrow \theta=(2 m+1) \frac{\pi}{10} The values belonging to [0,π][0, \pi] are θ=0,π10,π4,3π10,π2,7π10,3π4,9π10\theta=0, \frac{\pi}{10}, \frac{\pi}{4}, \frac{3 \pi}{10}, \frac{\pi}{2}, \frac{7 \pi}{10}, \frac{3 \pi}{4}, \frac{9 \pi}{10}, π,11π10,5π4,13π10,3π2,17π10,7π4,19π10,2π\pi, \frac{11 \pi}{10}, \frac{5 \pi}{4}, \frac{13 \pi}{10}, \frac{3 \pi}{2}, \frac{17 \pi}{10}, \frac{7 \pi}{4}, \frac{19 \pi}{10}, 2 \pi