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Question: Number of solution of the equation 2<sup>1ogx</sup> + 8 = \((x - 8)^{\frac{1}{1og_{10}2}}\) is...

Number of solution of the equation 21ogx + 8 = (x8)11og102(x - 8)^{\frac{1}{1og_{10}2}} is

A

1

B

2

C

3

D

4

Answer

1

Explanation

Solution

Q L.H.S.= f(x)

& R.H.S. = f–1(x)

\f(x) = f–1(x) = x

̃ (x8)1/log102(x - 8)^{1/\log_{10}2}= x

̃ 1log102\frac{1}{\log_{10}2} log10(x – 8) = log10x

̃ logx (x – 8) = log102

̃ x – 8 = 2 & x = 10

x = 10 is the solution.