Question
Question: number of positive integers which have the characteristic 4 when the base of log is 5...
number of positive integers which have the characteristic 4 when the base of log is 5
2500
Solution
The characteristic of logbN is the integer part of logbN. If the characteristic is k, it means k≤logbN<k+1.
In this problem, the base is 5 and the characteristic is 4. So, we have:
4≤log5N<5
To find the range of N, we exponentiate the inequality with base 5:
54≤5log5N<55
Since N is a positive integer, 5log5N=N. So, the inequality becomes:
54≤N<55
Calculate the values of 54 and 55:
54=5×5×5×5=625
55=5×5×5×5×5=3125
The inequality is therefore:
625≤N<3125
We are looking for the number of positive integers N that satisfy this condition. The integers N start from 625 and go up to 3124.
The set of integers is {625,626,627,…,3124}.
To find the number of integers in the range [a,b), which is a≤N<b, the number of integers is b−a.
In this case, a=625 and b=3125.
The number of integers is 3125−625.
Number of integers = 3125−625=2500.
Thus, there are 2500 positive integers that have the characteristic 4 when the base of the logarithm is 5.