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Question

Question: number of positive integers which have the characteristic 4 when the base of log is 5...

number of positive integers which have the characteristic 4 when the base of log is 5

Answer

2500

Explanation

Solution

The characteristic of logbN\log_b N is the integer part of logbN\log_b N. If the characteristic is kk, it means klogbN<k+1k \le \log_b N < k+1.

In this problem, the base is 5 and the characteristic is 4. So, we have:
4log5N<54 \le \log_5 N < 5

To find the range of NN, we exponentiate the inequality with base 5:
545log5N<555^4 \le 5^{\log_5 N} < 5^5

Since NN is a positive integer, 5log5N=N5^{\log_5 N} = N. So, the inequality becomes:
54N<555^4 \le N < 5^5

Calculate the values of 545^4 and 555^5:
54=5×5×5×5=6255^4 = 5 \times 5 \times 5 \times 5 = 625
55=5×5×5×5×5=31255^5 = 5 \times 5 \times 5 \times 5 \times 5 = 3125

The inequality is therefore:
625N<3125625 \le N < 3125

We are looking for the number of positive integers NN that satisfy this condition. The integers NN start from 625 and go up to 3124.
The set of integers is {625,626,627,,3124}\{625, 626, 627, \dots, 3124\}.

To find the number of integers in the range [a,b)[a, b), which is aN<ba \le N < b, the number of integers is bab - a.
In this case, a=625a = 625 and b=3125b = 3125.
The number of integers is 31256253125 - 625.

Number of integers = 3125625=25003125 - 625 = 2500.

Thus, there are 2500 positive integers that have the characteristic 4 when the base of the logarithm is 5.