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Chemistry Question on Structure of atom

Number of oxalic acid molecules in 100 mL100\, mL of 0.02 N0.02\, N oxalic acid are

A

6.023×10206.023 \times 10^{20}

B

6.023×10216.023 \times 10^{21}

C

6.023×10226.023 \times 10^{22}

D

6.023×10236.023 \times 10^{23}

Answer

6.023×10206.023 \times 10^{20}

Explanation

Solution

The correct answer is Option A) 6.023×10206.023 \times 10^{20}

To solve this problem first the molarity needs to be determined by the formula: Molarity=Valency factor/Normality​

Here, the Valency factor is 0.02 and the Normality is 2

Therefore, Molarity = 0.02/2 = 0.01M

Now, there's Avogadro number of molecules present in one molar solution = 6.023 × 1023

So, the number of oxalic acid molecules in 100 mL of 0.02 N oxalic acid solution will be

(0.01×6.023×1023​×100) / 1000 =6.023×1020.

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