Question

Number of moles of $MnO^{-}_4$ required to oxidise one mole of ferrous oxalate completely in acidic medium will be

• A. 0.6 mol
• B. 0.4 mole
• C. 7.5 moles
• D. 0.2 mole

Answer 1

Answer: (A)

0.6 mol

Answer 2

No. of moles of $MnO _{4}^{-}$required to oxidize one mole of $F eC _{2} O _{4}$ completely in acidic medium. $3 MnO _{4}^{-}+24 H ^{+}+5 F eC _{2} O _{4} \longrightarrow 3 Mn ^{+2}+12 H _{2} O +10 CO _{2}+5 Fe ^{+3}$ 5 moles of $F eC _{2} O _{4}$ reacts with 3 moles of $MnO _{4}^{-}$. 5moles of $FeC _{2} O _{4} \longrightarrow$ 3moles of $MnO _{4}^{-}$ 1mole of $FeC _{2} O _{4} \longrightarrow \frac{3}{5}$ moles of $MnO _{4}^{-}$ $\therefore$ The number of moles of $MnO _{4}^{-}$required to oxidize one mole of ferrous oxalate completely in the acidic medium will be 0.6 moles.