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Question: Number of moles of \(Mn{O_4}^ - \)required to oxidize one mole of ferrous oxalate completely in th...

Number of moles of MnO4−Mn{O_4}^ - required to oxidize one mole of ferrous oxalate
completely in the acidic medium will be:
A. 7.5  moles7.5\;moles
B. 0.2  moles0.2\;moles
C. 0.6  moles0.6\;moles
D. 0.4  moles0.4\;moles

Explanation

Solution

As we know that, the mole is the unit of measurement of the physical quantity designated as amount of substance. In practice, one mole of any kind of chemical species is about 6.022×10236.022 \times {10^{23}} atoms.

Step by step answer: Ferrous ion will always get oxidized to ferrate, +2,+3 + 2, + 3that means it losses one {e^\\_}, oxalate ion gets to carbon dioxide, carbon changes its oxidation number from +3  ,+4 + 3\;, + 4,but oxalate ion contains 2{e^\\_}, so it loses 2{e^\\_} that means 11 moles ferrous oxalate is going to lose 3{e^\\_}.
If we consider MnO4−Mn{O_4}^ - is in its 77 ionic state, and since the total charge of MnO4Mn{O_4} is−1 - 1.
Number of moles of MnO4−Mn{O_4}^ - required to oxidize one mole of FeC2O4Fe{C_2}{O_4} completely in an acidic medium. We see that5  mol5\;mol. Of FeC2O4Fe{C_2}{O_4} gives 33 mole ofMnO4−Mn{O_4}^ - . But when 11 mole of FeC2O4Fe{C_2}{O_4} is oxidized then it gives 35\dfrac{3}{5} moles ofMnO4−Mn{O_4}^ - , it means 0.60.6 moles ofMnO4−Mn{O_4}^ - .
3MnO−4+24H++5FeC2O4→3Mn+2+12H2O+10CO2+5Fe+33Mn{O^ - }_4 + 24{H^ + } + 5Fe{C_2}{O_4} \to 3M{n^{ + 2}} + 12{H_2}O + 10C{O_2} + 5F{e^{ + 3}}

5  moles  of  FeC2O4→3  moles  of  MnO−4 ⇒1  moles  of  FeC2O4→35  moles  MnO−4 ⇒1  moles  of  FeC2O4=  0.6  moles  of  MnO4−5\;moles\;of\;Fe{C_2}{O_4} \to 3\;moles\;of\;Mn{O^ - }_4\\\ \Rightarrow 1\;moles\;of\;Fe{C_2}{O_4} \to \dfrac{3}{5}\;moles\;Mn{O^ - }_4\\\ \Rightarrow 1\;moles\;of\;Fe{C_2}{O_4} = \;0.6\;moles\;of\;Mn{O_4}^ -

The mole concept is not necessarily restricted to material entities. We can speak of a mole of chemical reactions and so on. The number 6.022×10236.022 \times {10^{23}} is known as Avogadro number, it should be designated as Avogadro’s constant and expressed as mol−1mo{l^{ - 1}}
11 Moles of atoms or ions or molecules = atomic or molecular mass of it in grams or molar mass.

Therefore, the correct answer is C.

Note: Mole concept is very important and very useful. It includes boyle’s law, Charles law, Gay-Lussac law, principle of atomic conversion, limiting reagents, molarity, molality, mole fraction, normality, etc.