Question

Number of moles of methane required to produce 22g $CO_{2​(g)}$ after combustion is $x × 10^{−2}$ moles. The value of x is

Answer 1

$\text{CH}_4\,(g) + 2\text{O}_2\,(g) \rightarrow \text{CO}_2\,(g) + 2\text{H}_2\text{O}\,(l)$
$n_{\text{CO}_2} = \frac{22}{44} = 0.5 \, \text{moles}$
$\text{So moles of CH}_4 \text{ required} = 0.5 \, \text{moles}$
$\text{i.e., } 50 \times 10^{-2} \, \text{mole}$
$x = 50$