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Question

Chemistry Question on Redox reactions

Number of moles of K2Cr2O7K_2Cr_2O_7 reduced by one mole of Sn2+Sn^{2+} ions is

A

44564

B

3

C

44567

D

6

Answer

44564

Explanation

Solution

Cr2O72−+14H++3Sn2+−>2Cr3++3Sn4++7H2O {Cr_2O^{2-}_7 + 14H^{+} + 3Sn^{2+} -> 2Cr^{3+} + 3 Sn^{4+} + 7 H_2O} Thus, 1 mole of Sn2+ {Sn^{2+}} reduces 13\frac{1}{3} moles of K2Cr2O7 {K_2Cr_2O_7}